%!iTeXMac(project):altpdflatex
\documentclass[a4paper]{article}
\usepackage[mathletters]{ucs}
\usepackage[utf8]{inputenc}
\usepackage[upright,expert]{fourier}
\usepackage{longtable}
\usepackage{array}
\usepackage{multicol}
\usepackage{pst-node}
\usepackage{pst-circ050203}
\usepackage{vmargin}

\setmarginsrb{1cm}{1cm}{1cm}{1cm}{0cm}{0cm}{0cm}{0cm}
\pagestyle{empty}
\everymath{\displaystyle}
\newcommand{\derive}[2]{\ensuremath \frac{\mathrm{d}#1}{\mathrm{d}#2}}
\newcommand{\dert}[1]{\derive{#1}{t}}
\newcommand{\derpar}[2]{\ensuremath \frac{\partial #1}{\partial #2}}
\newcommand{\derivesec}[2]{\ensuremath \frac{\mathrm{d}^2 #1}{\mathrm{d}#2 ^2}}
\newcommand{\grad}{\ensuremath \overrightarrow{\mathrm{grad}} \,}

\begin{document}
\begin{center}
\texttitle{Électronique}
\end{center}

\begin{longtable}{|m{10cm}>{\centering}m{5cm}|}
\hline
\scalebox{0.8}{\begin{pspicture}(0,-1)(8,4.5)
\pnode(4,3.75){VP}
\pnode(4,3.25){VM}
\pnode(6.5,3.5){VS}
\OA[OAinvert=false,OAperfect=true](VP)(VM)(VS)
\pnode(0.5,3.75){E}
\wire(E)(VP)
\pnode(3,3.25){A}
\wire(A)(VM)
\pnode(3,2){B}
\wire(A)(B)
\pnode(3,0){C}
\ground(C)
\pnode(6.5,2){D}
\wire(D)(VS)
\pnode(7.5,3.5){F}
\wire(VS)(F)
\pnode(1,0){M1}
\ground(M1)
\pnode(1,3.75){VE}
\node(VE)
\pnode(7.2,0){M2}
\ground(M2)
\pnode(7.2,3.5){S}
\node(S)
\resistor[labeloffset=0](B)(C){$R_1$}
\resistor[labeloffset=0](B)(D){$R_2$}
\tension(M1)(VE){$v_e$}
\tension[labeloffset=-0.5](M2)(S){$v_s$}
\end{pspicture}}
&
Amplificateur non inverseur \\
$$
v_s = \frac{R_1 + R_2}{R_1}v_e
$$
\tabularnewline
\hline
\scalebox{0.8}{\begin{pspicture}(0,0.5)(7.5,4.5)
%\psgrid[subgriddiv=1,griddots=10]
\pnode(4,3.75){VP}
\pnode(3.5,3.25){VM}
\pnode(6.2,3.5){VS}
\OA[OAinvert=false,OAperfect=true](VP)(VM)(VS)
\pnode(0.5,3.75){E}
\wire(E)(VP)
\pnode(2.5,3.25){A}
\wire(A)(VM)
\pnode(3.5,2){B}
\wire(B)(VM)
\pnode(6.2,2){C}
\wire(B)(C)
\wire(C)(VS)
\pnode(7,3.5){D}
\wire(VS)(D)
\pnode(1.5,1.5){M1}
\pnode(1.5,3.75){VE}
\node(VE)
\tension(M1)(VE){$v_e$}
\ground(M1)
\pnode(6.5,3.5){S}
\node(S)
\pnode(6.5,1.5){M2}
\tension[labeloffset=-0.5](M2)(S){$v_s$}
\ground(M2)
\end{pspicture}}
&
Suiveur \\
$$
v_s = v_e
$$
\tabularnewline
\hline
\scalebox{0.8}{\begin{pspicture}(0.5,1)(8,5.5)
%\psgrid[subgriddiv=1,griddots=10]
\pnode(3.5,3.75){VM}
\pnode(3.5,3.25){VP}
\pnode(6,3.5){VS}
\OA[OAinvert=true,OAperfect=true](VM)(VP)(VS)
\pnode(3.5,5){A}
\wire(VM)(A)
\pnode(6,5){B}
\wire(B)(VS)
\pnode(7.5,3.5){D}
\wire(VS)(D)
\pnode(1,3.75){F}
\pnode(1.5,3.75){VE}
\node(VE)
\pnode(1.5,2){G}
\wire(F)(VE)
\pnode(3,2){M}
\pnode(3,3.25){J}
\wire(VP)(J)
\pnode(7,2){H}
\pnode(7,3.5){I}
\node(I)
\wire(J)(M)
\tension(G)(VE){$v_e$}
\tension[labeloffset=-0.5](H)(I){$v_s$}
\ground(M)
\ground(G)
\ground(H)
\resistor[labeloffset =0](A)(B){$R_2$}
\resistor[labeloffset =0](VE)(VM){$R_1$}
\end{pspicture}}
&
Amplificateur inverseur \\
$$
\frac{v_s}{v_e} = H = -\frac{R_2}{R_1}
$$
\tabularnewline
\hline
\scalebox{0.8}{\begin{pspicture}(-1,0)(8,5.5)
%\psgrid[subgriddiv=1,griddots=10]
\pnode(3.5,3.75){VM}
\pnode(3.5,3.25){VP}
\pnode(6.5,3.5){S}
\OA[OAinvert=true,OAperfect=true](VM)(VP)(S)
\pnode(3.5,5){A}
\wire(VM)(A)
\pnode(6.5,5){B}
\wire(B)(S)
\pnode(7.5,3.5){D}
\wire(S)(D)
\pnode(-1,3.75){F}
\pnode(0,3.75){VE}
\node(VE)
\pnode(0,1){G}
\wire(F)(VE)
\pnode(3.5,1){M}
\pnode(7,1){H}
\pnode(7,3.5){I}
\node(I)
\pnode(2,3.75){J}
\pnode(3,3.75){K}
\wire(J)(K)
\wire(K)(VM)
\pnode(2.5,2.5){L}
\pnode(3,2.5){O}
\wire(K)(O)
\pnode(1.5,2.5){N}
\wire(VP)(M)
\pnode(1.25,1){P}
\pnode(1.25,2.5){Q}
\node(Q)
\tension(G)(VE){$v_{e_1}$}
\tension(P)(Q){$v_{e_2}$}
\tension[labeloffset=-0.5](H)(I){$v_s$}
\ground(M)
\ground(G)
\ground(H)
\ground(P)
\resistor[labeloffset=0](A)(B){$R$}
\resistor[labeloffset=0](VE)(J){$R_1$}
\resistor[labeloffset=0](Q)(O){$R_2$}
\end{pspicture}}
&
Sommateur inverseur\\
$$
v_s = -\frac{R}{R_1}v_{e_1} - \frac{R}{R_2}v_{e_2}
$$
\tabularnewline
\hline
\scalebox{0.8}{\begin{pspicture}(-0.8,-0.1)(4.8,2.5)
%\psgrid[subgriddiv=1,griddots=10]
\pnode(0.5,0){M1}
\pnode(4,0){M2}
\wire(M1)(M2)
\pnode(0.5,2){VE}
\pnode(3,2){A}
\pnode(4,2){VS}
\wire(A)(VS)
\pnode(3,0){M3}
\tension(M1)(VE){$v_e$}
\tension[labeloffset=-0.5](M2)(VS){$v_s$}
\resistor[labeloffset=0](VE)(A){$R$}
\capacitor[labeloffset=-1](A)(M3){$C$}
\end{pspicture}}
&
Filtre passe-bas d'ordre 1\\
$$
\underline{H} = \frac{1}{1+j\frac{\omega}{{\omega}_0}} \mbox{ avec } {\omega_0} = \frac{1}{RC}
$$
\tabularnewline
\hline
\scalebox{0.8}{\begin{pspicture}(0,0)(8,6.5)
%\psgrid[subgriddiv=1,griddots=10]
\pnode(3.5,3.75){VM}
\pnode(3.5,3.25){VP}
\pnode(7,3.5){VS}
\OA[OAinvert=true,OAperfect=true](VM)(VP)(VS)
\pnode(3.5,5){A}
\pnode(6.5,5){B}
\pnode(1,3.75){VE}
\pnode(3.5,1){M}
\pnode(6.5,3.5){S}
\wire(VP)(M)
\wire(VM)(A)
\wire(B)(S)
\wire(S)(VS)
\pnode(1,1){M1}
\pnode(7,1){M2}
\tension(M1)(VE){$v_e$}
\tension[labeloffset=-0.5](M2)(VS){$v_s$}
\ground(M)
\ground(M1)
\ground(M2)
\resistor[labeloffset=0](VE)(VM){$R$}
\capacitor[labeloffset=1](A)(B){$C$}
\end{pspicture}}
&
Intégrateur\\
$$
v_s = -\frac{1}{RC}\int v_e\,\mathrm{d}t
$$
\tabularnewline
\hline
\scalebox{0.8}{\begin{pspicture}(-0.8,-0.1)(4.8,3.3)
%\psgrid[subgriddiv=1,griddots=10]
\pnode(0.5,0){M1}
\pnode(4,0){M2}
\wire(M1)(M2)
\pnode(0.5,2){VE}
\pnode(3,2){A}
\pnode(4,2){VS}
\wire(A)(VS)
\pnode(3,0){M3}
\tension(M1)(VE){$v_e$}
\tension[labeloffset=-0.5](M2)(VS){$v_s$}
\capacitor[labeloffset=0.8](VE)(A){$C$}
\resistor[labeloffset=0](A)(M3){$R$}
\end{pspicture}}
&
Filtre passe-haut d'ordre 1\\
$$
\underline{H} = \frac{j\frac{\omega}{{\omega}_0}}{1 + j\frac{\omega}{{\omega}_0}}
$$
\tabularnewline
\hline
\scalebox{0.8}{\begin{pspicture}(0,0)(8,6.5)
%\psgrid[subgriddiv=1,griddots=10]
\pnode(3.5,3.75){VM}
\pnode(3.5,3.25){VP}
\pnode(6.5,3.5){S}
\OA[OAinvert=true,OAperfect=true](VM)(VP)(S)
\pnode(1,3.75){VE}
\pnode(3.5,5){A}
\pnode(6.5,5){B}
\pnode(3.5,1){M}
\pnode(7,3.5){VS}
\wire(VP)(M)
\wire(VM)(A)
\wire(B)(S)
\wire(S)(VS)
\pnode(1,1){M1}
\pnode(7,1){M2}
\tension(M1)(VE){$v_e$}
\tension[labeloffset=-0.5](M2)(VS){$v_s$}
\ground(M)
\ground(M1)
\ground(M2)
\capacitor[labeloffset=1](VE)(VM){$C$}
\resistor[labeloffset=0](A)(B){$R$}
\end{pspicture}}
&
Dérivateur\\
$$
\begin{array}{c}
v_s = -RC\dert{v_e} \\
\underline{H} = -jRC\omega = -j\frac{\omega}{{\omega}_0}
\end{array}
$$
\tabularnewline
\hline
%\end{longtable}
%\begin{longtable}{|m{10cm}>{\centering}m{5cm}|}
%\hline
\scalebox{0.8}{\begin{pspicture}(1,-1.5)(5,1.5)
%\psgrid[subgriddiv=1,griddots=10]
\pnode(3,0){C}
\pnode(2,0){A}
\pnode(4,0){B}
\pnode(2,-0.5){AA}
\pnode(3,-0.5){CC}
\pnode(4,-0.5){BB}
\pnode(2,0.5){AAA}
\pnode(4,0.5){BBB}
\tension[labeloffset=-0.5](AA)(CC){$u_1$}
\tension[labeloffset=0.5](BB)(CC){$u_2$}
\tension(AAA)(BBB){$u = u_2 - u_1$}
\Zener[labeloffset=0](C)(A){}
\Zener[labeloffset=0](C)(B){}
\end{pspicture}}
&
Limiteur de tension\\
$$
-(v_s + v_z) \leq u \leq v_s + v_z
$$
\tabularnewline
\hline
\scalebox{0.8}{\begin{pspicture}(0,-3)(8,5.3)
%\psgrid[subgriddiv=1,griddots=10]
\pnode(3.5,3.75){VM}
\pnode(3.5,3.25){VP}
\pnode(6.5,3.5){S}
\OA[OAinvert=true,OAperfect=true](VM)(VP)(S)
\pnode(1,3.75){VE}
\wire(VE)(VM)
\pnode(7,3.5){VS}
\wire(S)(VS)
\pnode(2,-2){M}
\pnode(2,-1){R1}
\pnode(2,0){A}
\pnode(2,1){R2}
\pnode(2,2.8){B}
\wire(M)(R1)
\wire(A)(R2)
\wire(2,1)(3.5,1)
\wire(3.5,1)(VP)
\pnode(2,5){VCC}
\node(VCC)
\wire[intersect,intersectA=VE,intersectB=VM](B)(VCC)
\pnode(1,-2){M1}
\pnode(7,-2){M2}
\ground(M)
\ground(M1)
\ground(M2)
\rput(2.5,5){$+V_{cc}$}
\tension[labeloffset=0.5](M1)(VE){$v_e$}
\tension[labeloffset=-0.5](M2)(VS){$v_s$}
\resistor[labeloffset=0](R1)(A){$R_1$}
\resistor[labeloffset=0](R2)(B){$R_2$}
\end{pspicture}}
&
Comparateur simple\\
Apparition d'un cycle d'hystérésis
\tabularnewline
\hline
\scalebox{0.8}{\begin{pspicture}(0,-1)(8,4.5)
\pnode(4,3.75){VP}
\pnode(4,3.25){VM}
\pnode(6.5,3.5){S}
\OA[OAinvert=true,OAperfect=true](VP)(VM)(S)
\pnode(0.5,3.75){E}
\wire(E)(VP)
\pnode(3,3.25){A}
\wire(A)(VM)
\pnode(3,2){B}
\wire(A)(B)
\pnode(3,0){C}
\ground(C)
\pnode(6.5,2){D}
\wire(D)(S)
\pnode(6,3.5){E}
\pnode(7.5,3.5){F}
\wire(E)(F)
\pnode(1,0){M1}
\ground(M1)
\pnode(1,3.75){VE}
\node(VE)
\pnode(7.2,0){M2}
\ground(M2)
\pnode(7.2,3.5){VS}
\node(VS)
\resistor[labeloffset=0](B)(C){$R_1$}
\resistor[labeloffset=0](B)(D){$R_2$}
\tension[labeloffset=0.5](M1)(VE){$v_e$}
\tension[labeloffset=-0.5](M2)(VS){$v_s$}
\end{pspicture}}
&
Comparateur à hystérésis
\tabularnewline
\hline
\scalebox{0.8}{\begin{pspicture}(0,-1)(8,6.5)
%\psgrid[subgriddiv=1,griddots=10]
\pnode(3.5,3.75){VP}
\pnode(6.5,3.5){VS}
\pnode(3.5,3.25){VM}
\OA[OAinvert=true,OAperfect=true](VP)(VM)(VS)
\pnode(1,3.75){VE}
\pnode(1,0){M1}
\node(VE)
\wire[intensity=true,intensitylabel=$i_e$](VE)(2,3.75)
\wire(2,3.75)(VP)
\pnode(2,5){A}
\pnode(6.5,5){B}
\wire(2,3.75)(A)
\wire(B)(VS)
\wire(VM)(2,3.25)
\pnode(2,2){C}
\wire(2,3.25)(C)
\pnode(2,0){M}
\pnode(6.5,2){D}
\wire(D)(6.5,3.5)
\ground(M)
\ground(M1)
\pnode(7.2,0){M2}
\ground(M2)
\pnode(7.2,3.5){S}
\wire(VS)(S)
\resistor[labeloffset=0](A)(B){$R_1$}
\resistor[labeloffset=0](C)(D){$R_2$}
\resistor[labeloffset=0](M)(C){$R_3$}
\tension[labeloffset=0.5](M1)(VE){$v_e$}
\tension[labeloffset=-0.5](M2)(S){$v_s$}
\end{pspicture}}
&
Résistance négative \\
$$
v_e = -R' i_e
$$
\tabularnewline
\hline
\end{longtable}

\end{document}